7[3-(5+4x)]-4x=-16+2(1-16x)

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Solution for 7[3-(5+4x)]-4x=-16+2(1-16x) equation:


Simplifying
7[3 + -1(5 + 4x)] + -4x = -16 + 2(1 + -16x)
7[3 + (5 * -1 + 4x * -1)] + -4x = -16 + 2(1 + -16x)
7[3 + (-5 + -4x)] + -4x = -16 + 2(1 + -16x)

Combine like terms: 3 + -5 = -2
7[-2 + -4x] + -4x = -16 + 2(1 + -16x)
[-2 * 7 + -4x * 7] + -4x = -16 + 2(1 + -16x)
[-14 + -28x] + -4x = -16 + 2(1 + -16x)

Combine like terms: -28x + -4x = -32x
-14 + -32x = -16 + 2(1 + -16x)
-14 + -32x = -16 + (1 * 2 + -16x * 2)
-14 + -32x = -16 + (2 + -32x)

Combine like terms: -16 + 2 = -14
-14 + -32x = -14 + -32x

Add '14' to each side of the equation.
-14 + 14 + -32x = -14 + 14 + -32x

Combine like terms: -14 + 14 = 0
0 + -32x = -14 + 14 + -32x
-32x = -14 + 14 + -32x

Combine like terms: -14 + 14 = 0
-32x = 0 + -32x
-32x = -32x

Add '32x' to each side of the equation.
-32x + 32x = -32x + 32x

Combine like terms: -32x + 32x = 0
0 = -32x + 32x

Combine like terms: -32x + 32x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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